Consider a uniformly charged non-conducting semicircular arc with radius r and total negative charge Q. The charge on a small segment with angle θ is labeled δq. Determine the magnitude of the electric field. The total charge is 53.2μC, the radius of the semicircle is 84 cm, and the Coulomb constant is 8.987*10^9 Nm^2/C^2.

Question

Irvin Arias

Physics

12 December, 22:58

Consider a uniformly charged non-conducting semicircular arc with radius r and total negative charge Q. The charge on a small segment with angle θ is labeled δq. Determine the magnitude of the electric field. The total charge is 53.2μC, the radius of the semicircle is 84 cm, and the Coulomb constant is 8.987*10^9 Nm^2/C^2.

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Answers (1)

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Henry Clark · Answer 1

Answer: Magnitude of electric field = 6.77*10^11N/C

Explanation: Electric field = E = KQ / r ^2

Given:

Total charge Q=53.2nc

Radius 84cm = 0.84m

Coulombs constant K = 8.987x10^9NmC^-1

E = ((8.987*10^9) * 53.2) / (0.84^2)

E = (4. 777 * 10 ^ 9) / 0.7056

E = 6.77 * 10^ 11 NC^-1