Ask Question
10 August, 07:03

Henry, whose mass is 95 kg, stands on a bathroom scale in an elevator. The scale reads 830 N for the first 3.0 s after the elevator starts moving, then 930 N for the next 3.0 s. What is the elevator's velocity 6.0 s after starting?

+4
Answers (1)
  1. 10 August, 07:27
    0
    The elevator's velocity after 6 seconds is 3.189m/s

    Explanation:

    Using Newton's 2nd law:Fnet = ma

    Mg - N = ma

    Where m = mass

    N = normal force

    a = acceleration

    g = acceleration due to gravity

    Substituting the given values and finding acceleration

    (95kg) (9.8m/s^2) - 830N = 95kg x a

    a = (931 - 830) / 95

    a = 101/95

    a = 1.063m/s^2

    After 3 seconds, the weight 0f the person is equal to the actual weight of the person, thus the elevator will be moving at a constant velocity.

    Using kinematic equation:

    V = u + at

    Where V = final velocity

    U = initial velocity = 0

    a = acceleration

    t = time

    V = 0 + 1.063 * 3

    V = 3.189m/s

    This velocity does not change. The elevator travels the test of the time at the same velocity. Therefore, the velocity at 6 seconds = 3.189m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Henry, whose mass is 95 kg, stands on a bathroom scale in an elevator. The scale reads 830 N for the first 3.0 s after the elevator starts ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers