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4 August, 04:49

We push a 38.4-kg box across the floor at constant velocity. If we are pushing a horizontal force of 238 N, find the coefficient of kinetic friction between the box and the floor.

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  1. 4 August, 05:17
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    Answer: 0.62

    Explanation:

    Coefficient of friction is defined as the ratio of the moving force (Fm) acting on a body to the normal reaction (R).

    Note that the normal reaction acts vertically on the object and is equal to the objects weight (W) i. e W=R

    Since W = mg, W = 38.4 * 10

    W = 384N = R

    Normal reaction = 384N

    The horizontal force acting on the body will be the moving force which is 238N

    Coefficient of friction = Fm/R

    Coefficient of friction = 238/384

    Coefficient of friction = 0.62

    Therefore, coefficient of kinetic friction between the box and the floor is 0.62
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