A coin of mass 0.05 kg is placed at a radius r = 0.1m meter on a horizontal turntable which is turning uniformly at a rate of one revolution every 1.5 s. The coin does not slip. The net force on the coin is?

Answer:F=0.0882kg

Explanation:

The period it takes to make one revolution is 1.5 seconds / revolutions,

v = r * (change in angle / change in time)

the change in angle is 2pi, for one whole revolution. the time is 1.5 second per revolution, and the radius is 0.1.

v = (2 * pi * 0.1 cm * / 1.5second

v = 0.42m/s

a=v^2/r

a=0.42^2 / 0.1 = 1.764m/s2

F=ma

F=0.05*1.764

F=0.0882kg