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25 May, 15:34

How much heat energy, in kilojoules, is required to convert 46.0 gg of ice at - -18.0 ∘C∘C to water at 25.0 ∘C∘C?

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  1. 25 May, 15:57
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    1. Energy for 18 to 0 * C

    Q = M * Cs * T

    (46) (2.09) (18) = 1.73 kj

    2. Fusion Energy

    Q = M * Change in Fusion Enthalpy of Fusion Given = 334 J

    (46) (334 j) = 15.36 KJ

    3. Energy for 0 to 25 * C

    (46) (4.18) (25) = 4.807 kj

    4. Add all of it up

    1.73 + 15.36 + 4.807 = 21.89 kj

    Is the answer 21.89 KJ
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