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4 February, 20:03

Find the torque required for the shaft to transmit 40 kW when (a) The shaft speed is 2500 rev/min. (b) The shaft speed is 250 rev/min.

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  1. 4 February, 20:14
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    (a) 152.85 Nm

    (b) 1528.5 Nm

    Explanation:

    According to the formula of power

    P = τ ω

    ω = 2 π f

    (a) f = 2500 rpm = 2500 / 60 = 41.67 rps

    So, 40 x 1000 = τ x 2 x 3.14 x 41.67

    τ = 152.85 Nm

    (b) f = 250 rpm = 250 / 60 = 4.167 rps

    So, 40 x 1000 = τ x 2 x 3.14 x 4.167

    τ = 1528.5 Nm
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