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28 August, 02:03

While spinning down from 500 rpm to rest, a flywheel does 3.9 kj of work. this flywheel is in the shape of a solid uniform disk of radius 1.2 m. what is the mass of this flywheel?

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  1. 28 August, 02:28
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    The answer is 4.0 kg since the flywheel comes to rest the kinetic energy of the wheel in motion is spent doing the work. Using the formula KE = (1/2) I w².

    Given the following:

    I = the moment of inertia about the axis passing through the center of the wheel; w = angular velocity; for the solid disk as I = mr² / 2 so KE = (1/4) mr²w². Now initially, the wheel is spinning at 500 rpm so w = 500 * (2*pi / 60) rad / sec = 52.36 rad / sec.

    The radius = 1.2 m and KE = 3900 J

    3900 J = (1/4) m (1.2) ² (52.36) ²

    m = 3900 J / (0.25) (1.2) ² (52.36) ²

    m = 3.95151 ≈ 4.00 kg
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