Ask Question
18 May, 19:03

The uniform dresser has a weight of 91 lb and rests on a tile floor for which μs = 0.25. If the man pushes on it in the horizontal direction θ = 0∘, determine the smallest magnitude of force F needed to move the dresser. Also, if the man has a weight of 151 lb, determine the smallest coefficient of static friction between his shoes and the floor so that he does not slip.

+4
Answers (1)
  1. 18 May, 19:11
    0
    F = 22.75 lb

    μ₁ = 0.15

    Explanation:

    The smallest force required to move the dresser must be equal to the force of friction between the man and the dresser. Therefore,

    F = μR

    F = μW

    where,

    F = Smallest force needed to move dresser = ?

    μ = coefficient of static friction = 0.25

    W = Weight of dresser = 91 lb

    Therefore,

    F = (0.25) (91 lb)

    F = 22.75 lb

    Now, for the coefficient of static friction between shoes and floor, we use the same formula but with the mas of the man:

    F = μ₁W₁

    where,

    μ₁ = coefficient of static friction between shoes and floor

    W₁ = Weight of man = 151 lb

    Therefore,

    22.75 lb = μ₁ (151 lb)

    μ₁ = 22.75 lb/151 lb

    μ₁ = 0.15
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The uniform dresser has a weight of 91 lb and rests on a tile floor for which μs = 0.25. If the man pushes on it in the horizontal ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers