A 1000.-kilogram car traveling 20.0 meters per second east experiences an impulse of 2000. newton • seconds west. What is the final velocity of the car after the impulse has been applied?

(1) 18.0 m/s east

(2) 19.5 m/s east

(3) 20.5 m/s west

(4) 22.0 m/s west

So the formula is equal to

M1v1 + I = m2v2

Where m is the mass of the object

V is the velocity of the object

I is the impulse applied

(1000 kg) (20 m/s) - 2000 = m2v2

20000 - 2000 = m2v2

18000 = m2v2

Since the car did change its mass, m1 = m2

18000 = (1000) v2

V2 = 18 m/s east