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9 April, 17:22

A battery does 2.186 J of work to transfer 0.033 C of charge from the negative to the positive terminal. What is the emf of this battery?

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  1. 9 April, 17:43
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    66.24 Volts

    Explanation:

    W = Amount of work done in moving the charge from negative to positive terminal = 2.186 J

    Q = Amount of charge being moved from negative to positive charge = 0.033 C

    ΔV = EMF of the battery

    Amount of work done in moving the charge from negative to positive terminal is given as

    W = Q ΔV

    2.186 = (0.033) ΔV

    ΔV = 66.24 Volts
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