Isaac throws an apple straight up from 1.0 m above the ground, reaching a maximum height of 35 meters. Neglecting air resistance, what is the ball's velocity when it hits the ground?

26.2005 m/s will be the velocity of the apple right when it hits the ground and the initial velocity would be 25.8235 m/s

so Vf=26.2005

and Vi=25.8235

the velocity difference is due to the apple having an initial height of 1 meter

So total height = 35+1 = 36 m

so using the formula, v^2=u^2+2as

we got = > v^2 = 0 + 2*10*36

v = 26.83 m/s

so the final velocity will be 26.83 m/s!