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23 November, 09:13

Determine the direction of the effective value of g⃗ at a latitude of 45 ∘ North on the Earth.

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  1. 23 November, 09:22
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    To solve this, we simply use trigonometry

    the effective value of g along the 45° angle is

    g eff = g / sin 45

    g eff = g / (√2 / 2)

    g eff = 2g / √2

    g eff = g √2 ≈ 6.94 m/s²
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