A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s2 for 20 s. It then proceeds at constant speed for 1100 m before slowing down at 2.2 m/s2 until it stops at the station.

How much time does it take the train to go between the stations?

Express your answer using two significant figures. The answer is NOT 20s, as was answered and "verified" previously.

Question

Mauricio Reid

Physics

31 July, 23:49

A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s2 for 20 s. It then proceeds at constant speed for 1100 m before slowing down at 2.2 m/s2 until it stops at the station.

How much time does it take the train to go between the stations?

Express your answer using two significant figures. The answer is NOT 20s, as was answered and "verified" previously.

+5

Answers (1)

Know the Answer?

Jayvion Moody · Answer 1

It accelerates from rest at 1.1 m/s^2 for 20s.

s = at^2/2

s = (.5) (1.1) (20) ^2 = 220m

then it travels 1100m

Then it slows down at 2.2m/s^2 until it stops at the station.

Calculate the train's speed:

v = at

v = (1.1) (20) = 22m/s

Now, calculate the time to stop:

v = at

t = 22/2.2 = 10s

s = t (u+v) / 2

s = 10 (0+22) / 2 = 110m

(A) Total distance = 220 + 1100+110 = 1430m

(B) Time = 20 + 1100/22 + 10 = 80s