An iron anchor of density 7890.00 kg/m3 appears 299 N lighter in water than in air. (a) What is the volume of the anchor? (b) How much does it weigh in air?

weigh is 2353.13 N

Explanation:

Given data

density = 7890.00 kg/m3

lighter = 299 N

to find out

the volume of the anchor and weigh in air

solution

from question we can say that

apparent weight = actual weight - buoyant force

we know weight = mg and buoyant force = water density * g

so volume of anchor is = actual weight - apparent weight / buoyant force

volume of anchor is = 299 / 1000 * 9.81

volume of anchor is = 0.0304791 m³

and

weight of anchor is mg

here mass m = density Fe g

density Fe = 7870 from table 14-1

so weight = 7870 * 0.0304791 * 9.81

weigh is 2353.13 N