Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is Sasha's tangential speed?

-0.9 m/s

-1.3 m/s

-2.7 m/s

Question

Mina

Physics

14 October, 05:46

Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is Sasha's tangential speed?

-0.9 m/s

-1.3 m/s

-2.7 m/s

+4

Answers (1)

Know the Answer?

Jacqueline Edwards · Answer 1

Answer: 2.7 m/s

Explanation:

Given the following:

Period (T) = 8.2 seconds

Radius = 3.5 m

The tangential speed is given as:

V = Radius * ω

ω = angular speed = (2 * pi) / T

ω = (2 * 22/7) / 8.2

ω = 6.2857142 / 8.2

ω = 0.7665505

Therefore, tangential speed (V) equals;

r * ω

3.5 * 0.7665505 = 2.6829268 m/s

2.7 m/s

Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is Sasha's tangential speed?-0.9 m/s-1.3 m/s-2.7 m/s

Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is Sasha's tangential speed?

-0.9 m/s

-1.3 m/s

-2.7 m/s