James m = 85.0 kg and ramon m = 59.0 kg are 20.0 m apart on a frozen pond. midway between them is a mug of their favorite beverage. they pull on the ends of a light rope stretched between them. ramon pulls on the rope to give himself a speed of 1.20 m/s. what is james's speed?

Question

Barrett Downs

Physics

22 April, 16:13

James m = 85.0 kg and ramon m = 59.0 kg are 20.0 m apart on a frozen pond. midway between them is a mug of their favorite beverage. they pull on the ends of a light rope stretched between them. ramon pulls on the rope to give himself a speed of 1.20 m/s. what is james's speed?

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Makenzie Velez · Answer 1

You can use conservation of momentum, Ramon has a momentum of m * v = 59.0 * 1.20 = 70.8. James must have that same momentum so m * v = p - - >

p / m = v - - > 70.8 / 85.0 = 0.83 m/s for James