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7 July, 23:26

If the gravitational field strength at the top of Mount Everest is 9.772 N/kg, approximately how tall (in feet) is

the mountain?

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  1. 7 July, 23:43
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    The height of the Everest mountain is, x = 8514.087 m

    Explanation:

    Given data,

    The gravitational field strength at the top of mount Everest, gₓ = 9.772 m/s²

    The formula for gravitational field strength is,

    gₓ = GM / (R+x) ²

    Where, x is the height from the surface of the Earth

    Therefore,

    (R+x) ² = GM/gₓ

    x = √ (GM/gₓ) - R

    Substituting the values,

    x = √ (6.67408 x 10⁻¹¹ X 5.972 x 10²⁴ / 9.772) - 6.378 x 10⁶

    x = 8514.087 m

    Therefore, the height of the Everest mountain is, x = 8514.087 m
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