A weightlifter presses a 400 n weight 0.5 m over his head in 2 seconds, what is the power of the weight lifter

There are two ways to solve this problem. First we write the given.

Given: Force F = 400 N; Height h = 0.5 m; Time t = 2 s

Formula: P = W/t; but Work W = Force x distance or W = f x d

Weight is also a Force, therefore: W = mg, solve for Mass m = ?

m = w/g m = 400 N/9.8 m/s² m = 40.82 Kg

P = W/t = F x d/t = mgh/t P = (40.82 Kg) (9.8 m/s²) / 2 s

P = 100 J/s or 100 Watts