How much helium gas would it take to fill a gas balloon with a volume of 11:0 cm3 when the temperature is 41.0◦c and the atmospheric pressure is 790 mm hg? answer in units of mol?

Temperature in Kelvin = 41+273 = 314K

Volume in liter = 11/1000 = 0.011L

Pressure in atmosphere = 790 mmhg = 1atm

Gas constant (R) = 0.082 L-atm-K⁻¹-mol⁻¹

Using ideal gas law equation,

PV=nRT

1*0.011 = n*0.082*314

n = 0.011/0.082*314

n = 4.27*10⁻⁴ moles.

∴ mass of helium gas required = n*4 = 4.27*10⁻⁵*4 = 1.708*10⁻⁴ gram.