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27 May, 16:30

Assuming 100% efficient energy conversion, how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery?

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  1. 27 May, 16:37
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    Complete question is;

    Assuming 100% efficient energy conversion how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery with power rating, 12 V, 50 Ampere-minutes.

    Answer:

    Amount of water required to charge the battery = 7.35 m³

    Explanation:

    The formula for Potential energy of the water at that height = mgh

    Where;

    m = mass of the water

    g = acceleration due to gravity = 9.8 m/s²

    h = height of water = 50 cm = 0.5 m

    We know that in density, m = ρV

    Where;

    ρ = density of water = 1000 kg/m³

    V = volume of water

    So, potential energy is now given as;

    Potential energy = ρVgH = 1000 * V * 9.8 * 0.5 = (4900V) J

    Now, formula for energy of the battery is given as;

    E = qV

    We are given;

    q = 50 A. min = 50 * 60 = 3,000 C

    V = 12 V

    Thus;

    qV = 3,000 * 12 = 36,000 J

    E = 36,000 J

    At a 100% conversion rate, the energy of the water totally powers the battery.

    Thus;

    (4900V) = (36,000)

    4900V = 36,000

    V = 36,000/4900

    V = 7.35 m³
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