The pressure on a gas at - 62◦c is doubled, but its volume is held constant. what will the final temperature be in degrees celsius? answer in units of ◦c.

We know that the relation between pressure, volume and temperature is constant for ideal gases, so then

P1*V1/T1 = P2*V2/T2

As the volume is held constant, we will have:

P1/T1 = P2/T2

As the pressure is doubled and the temperature in kelvins is 211.15 K, then:

P1/211.15 = 2*P1/T2

T2 = 2*211.15 = 422.3 K

T2 = 422.3 - 273.15 = 149.15

So the final temperature reaches 149.15 ÂşC