When a charged particle moves at an angle of 11° with respect to a magnetic field, it experiences a magnetic force of magnitude f. at what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 1.6f? °?

Question

Nathaly Cochran

Physics

7 August, 02:08

When a charged particle moves at an angle of 11° with respect to a magnetic field, it experiences a magnetic force of magnitude f. at what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 1.6f? °?

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Answers (1)

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Roman Tate · Answer 1

1) F=q[vB], where q - > charge, v-> velocity, B-> magnetic field. [, ] - > cross product.

2) f=q*v*B*sin (11°) {1}

3) 1.6f=q*v*B*sin (alpha) {2}

4) {2} / {1} - > 1.6=sin (alpha) / sin (11°) or sin (alpha) = 1.6*sin (11°) - - > alpha=arcsin (1.6*sin (11°))

So, alpha=17.7°=18°