Two people of different masses sit on a seesaw. m1, the mass of person 1, is 93 kg, m2 is 44 kg, d1 = 0.8 m, and d2 = 1.2 m. the mass of the board is negligible. (a) what is the magnitude of the torque about the pivot (location

a. due to the gravitational force on person 1? |τa, 1| = n · m

Question

Annika Dyer

Physics

7 August, 04:31

Two people of different masses sit on a seesaw. m1, the mass of person 1, is 93 kg, m2 is 44 kg, d1 = 0.8 m, and d2 = 1.2 m. the mass of the board is negligible. (a) what is the magnitude of the torque about the pivot (location

a. due to the gravitational force on person 1? |τa, 1| = n · m

+2

Answers (1)

Know the Answer?

Aracely Harvey · Answer 1

Torque = Force * Distance

Force = Weight = m1*g = 93*9.81 = 912.33 N

Distance from the pivot to person 1, d1 = 0.8 m

Therefore,

Torque = 912.33*0.8 = 729.864 N. m

Two people of different masses sit on a seesaw. m1, the mass of person 1, is 93 kg, m2 is 44 kg, d1 = 0.8 m, and d2 = 1.2 m. the mass of the board is negligible. (a) what is the magnitude of the torque about the pivot (locationa. due to the gravitational force on person 1? |τa, 1| = n · m

Two people of different masses sit on a seesaw. m1, the mass of person 1, is 93 kg, m2 is 44 kg, d1 = 0.8 m, and d2 = 1.2 m. the mass of the board is negligible. (a) what is the magnitude of the torque about the pivot (location

a. due to the gravitational force on person 1? |τa, 1| = n · m