In an isolated system, Bicycle 1 and Bicycle 2, each with a mass of 10 kg,

collide. Bicycle 1 was moving to the right at 5 m/s, while Bicycle 2 was

moving to the left at 3 m/s. What is the magnitude of their combined

momentum before the crash?

Answer: 20 kgm/s

Explanation:

Given that M1 = M2 = 10kg

V1 = 5 m/s, V2 = 3 m/s

Since momentum is a vector quantity, the direction of the two object will be taken into consideration.

The magnitude of their combined

momentum before the crash will be:

M1V1 - M2V2

Substitute all the parameters into the formula

10 * 5 - 10 * 3

50 - 30

20 kgm/s

Therefore, the magnitude of their combined momentum before the crash will be 20 kgm/s