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22 April, 19:00

It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the elevator during the process?

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  1. 22 April, 19:09
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    P=4801.5

    Explanation:

    Given:

    work done = W = 100,832 J

    time = 21.0 sec

    Find:

    P = ?

    Formula:

    P = W/t

    Solution:

    P = W/t

    P = 100,832/21.0

    = 4801.52 J/s or Watts
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