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10 February, 19:05

If a constant friction force of magnitude 11 Newtons is exerted on the block by the surface, find the magnitude of the acceleration of the block. Answer in units of m/s 2

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  1. 10 February, 19:34
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    acceleration a = 3.67 m/s^2

    Completed Question:

    A block of mass 3 kg, which has an initialspeed of 6 m/s at timet = 0, slides on ahorizontal surface. If a constant friction force of magnitude 11 Newtons is exerted on the block by the surface, find the magnitude of the acceleration of the block. Answer in units of m/s 2

    Explanation:

    Force = mass * acceleration

    F = ma ... 1

    Given that;

    Force F = 11 N

    mass m = 3 kg

    Acceleration a can be derived from equation 1

    Making a the subject of formula;

    a = F/m

    Substituting the given values;

    a = 11N/3kg

    a = 3.66666 ... m/s^2

    acceleration a = 3.67 m/s^2
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