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16 January, 17:30

Eight joules of work is required to stretch a spring 0.5 meter from its natural length. Find the work required to stretch the spring an additional 0.40 meter.

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  1. 16 January, 17:49
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    Additional Work done to stretch the spring 0.4m is 6.4J

    Explanation:

    Given -

    Work done to stretch a spring, W1 = 8J

    Distance, d = 0.5m

    Distance2, x = 0.4m

    Work done 2, W2 = ?

    Using Hooke's law,

    Work done = k x

    where k is spring constant

    For distance 0.5m:

    8 J = k X 0.5m

    k = 8/0.5 = 16 J/m

    For distance 0.4m:

    W2 = 16 X 0.4 J

    W2 = 6.4J

    Additional Work done to stretch the spring 0.4m is 6.4J
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