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2 December, 02:07

A person takes a trip, driving with a constant speed of 94.5 km/h except for a 22.0 min rest stop. If the person's average speed is 65.1 km/h, how much time is spent on the trip and how far does the person travel?

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  1. 2 December, 02:25
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    From the average speed you can fix an equation:

    Average speed = distance / time

    You know the average speed = 65.1 kg / h, then

    65.1 = distance / total time,

    where total time is the time traveling plus 22.0 minutes

    Call t the time treavelling and pass 22 minutes to hours:

    65.1 = distance / [t + 22/60] = = > distance = [t + 22/60]*65.1

    From the constant speed, you can fix a second equation

    Constant speed = distance / time traveling

    94.5 = distance / t = = > distance = 94.5 * t

    The distance is the same in both equations, then you have:

    [t + 22/60] * 65.1 = 94.5 t

    Now you can solve for t.

    65.1t + 22*65.1/60 = 94.5t

    94.5t - 65.1t = 22*65.1/60

    29.4t = 23.87

    t = 23.87 / 29.4

    t = 0.812 hours

    distance = 94.5 km/h * 0.812 h = 76.7 km

    Answers: 1) 0.81 hours, 2) 76.7 km
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