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21 May, 19:10

The runner reaches the first camera, at the 500 m mark, at 9:03:05 a. m. and the second camera, at the 600 m mark, at 9:03:25 a. m. What is her average speed over that time interval

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  1. 21 May, 19:22
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    Distance travelled = 600 - 500 = 100 m

    Time taken = 9:03:25 a. m. - 9:03 : 05 a. m.

    = 20 s

    average speed = distance / time taken

    = 100 / 20 m / s

    = 5 m / s
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