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31 March, 11:41

A cart on an air track is moving at 0.5m/s when the air issuddenly turned off. THe cart comes to rest in 1m. The experimentis repeated with the cart moving at 1 m/s when the air is turnedoff. How far does the cart travel before coming to rest?

a) 1 m

b) 2 m

c) 3 m

d) 4 m

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Answers (1)
  1. 31 March, 11:55
    0
    D = 4 m

    Explanation:

    Speed of cart in air track v₁ = 0.5 m/s

    Speed of cart moved when air is turned off v₂ = 1 m/s

    The distance travelled by the cart is d₁ = 1 m

    Work done (W) = F x d

    Work done is equal to the kinetic energy

    F x d = 1/2mv²

    velocity is directly proportional to distance

    therefore,

    v₁² / v₂² = d₁ / d₂

    d₂ = d₁v₂² / v₁²

    = 1 m x (1 m / s) ² / (0.5 m/s) ²

    = 4 m
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