On a certain game show, contestants spin a wheel when it is their turn. One contestant gives the wheel an initial angular speed of 3.40 rad/s. The angular acceleration of the wheel is - 0.736 rad/s^2. Through what angle has the wheel turned when its angular speed is 2.10 rad/s?

Question

Hunter Avila

Physics

26 June, 21:11

On a certain game show, contestants spin a wheel when it is their turn. One contestant gives the wheel an initial angular speed of 3.40 rad/s. The angular acceleration of the wheel is - 0.736 rad/s^2. Through what angle has the wheel turned when its angular speed is 2.10 rad/s?

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Answers (1)

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Jaydan Delgado · Answer 1

The wheel has turned θ = 4.84 rad when its angular speed is ωf = 2.1 rad/s

Explanation:

ωi = 3.4 rad/s

ωf = 2.1 rad/s

α = - 0.736 rad/s²

ωf = ωi - α*t

(ωf-ωi) / α=t

t = 1.76 s

θ = ωi * t - α * t²/2

θ = 4.84 rad