During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300m/s^2 (about 30 times free-fall acceleration called 30g). The fuel burned for 8.0 s. Find the height of the Terrier-Sandhawk rocket at the end of fuel burn.

Question

Frances Morgan

Physics

12 February, 11:51

During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300m/s^2 (about 30 times free-fall acceleration called 30g). The fuel burned for 8.0 s. Find the height of the Terrier-Sandhawk rocket at the end of fuel burn.

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Answers (1)

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Gerardo Galloway · Answer 1

Initial launch velocity, u = 0

Acceleration, a = 300 m/s²

Duration, t = 8.0 s

The distance traveled is

h = ut + (1/2) * a*t²

= (0 m/s) * (8 s) + 0.5 * (300 m/s²) * (8 s) ²

= 9600 m

Answer: 9600 m