A color television tube generates some X-rays when its electron beam strikes the screen. What is the shortest wavelength of these X-rays, in meters, if a 31 kV potential is used to accelerate the electrons? (Note that TVs have shielding to prevent these X-rays from reaching viewers.)

Question

Helena

Physics

22 May, 01:57

A color television tube generates some X-rays when its electron beam strikes the screen. What is the shortest wavelength of these X-rays, in meters, if a 31 kV potential is used to accelerate the electrons? (Note that TVs have shielding to prevent these X-rays from reaching viewers.)

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Answers (1)

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Spears · Answer 1

Answer: 4.0024 x 10^ - 11 m or 0.040024 nm

Explanation:

λ = h c/ΔE

λ = wave lenght

h = 6.626 x 10 ^ - 34 m² kg / s = planck constant

ΔE = 31 keV potential (1 keV = 1.6021 x 10^-16J)

c = velocity of light = 3 x 10⁸ m/s

substitute gives

λ = 6.626 x 10 ^ - 34 m² kg / s x 3 x 10⁸ m/s = 4.0024 x 10^ - 11 m

31 x 1.6021x10^-16 J