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7 June, 20:45

What is the approximate weight of the air inside the tire in English Engineering Units (tire outside diameter = 49", rim diameter-22", tire width-19" see: tire side view. ndf?

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  1. 7 June, 20:54
    0
    1.265 Pounds

    Explanation:

    Data provided:

    Tire outside diameter = 49"

    Rim diameter = 22"

    Tire width = 19"

    Now,

    1" = 0.0254 m

    thus,

    Tire outside radius, r₁ = 49"/2 = 24.5" = 24.5 * 0.0254 = 0.6223 m

    Rim radius, r₂ = 22" / 2 = 11" = 0.2794 m

    Tire width, d = 19" = 0.4826 m

    Now,

    Volume of the tire = π (r₁² - r₂²) * d

    on substituting the values, we get

    Volume of air in the tire = π (0.6223² - 0.2794²) * 0.4826 = 0.46877 m³

    Also,

    Density of air = 1.225 kg/m³

    thus,

    weight of the air in the tire = Density of air * Volume air in the tire

    or

    weight of the air in the tire = 1.225 * 0.46877 = 0.5742 kg

    also,

    1 kg = 2.204 pounds

    Hence,

    0.5742 kg = 0.5742 * 2.204 = 1.265 Pounds
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