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Today, 14:51

A ball is rolling down a hill at + 1.0 m/s, The ball is uniformly accelerating at

+4.9 m/s?, What will the ball's velocity be 4.0 s later?

+8.9 x 100° m/s

+2.0 x 10^1 m/s

+2.1 x 10^1 m/s

-1.9 x 10^1 m/s

+2
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  1. Today, 14:58
    0
    2.1*10¹ m/s

    Explanation:

    Given:

    v₀ = 1.0 m/s

    a = 4.9 m/s²

    t = 4.0 s

    Find: v

    v = at + v₀

    v = (4.9 m/s²) (4.0 s) + (1.0 m/s)

    v = 20.6 m/s

    Rounded to two significant figures, the velocity is 21 m/s.

    In scientific notation, the velocity is 2.1*10¹ m/s.
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