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8 September, 17:05

A car's 30.0-kg front tire is suspended by a spring with spring constant k=1.00x10^5 N/m. At what speed is the car moving if washboard bumps on the road every 0.750 m drive the tire into a resonant oscillation?

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  1. 8 September, 17:21
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    we know the equation for the period of oscillation in SHM is as follows:

    T = 2 * pi * sqrt (mass/k)

    we know f = 1/T, so f = 1 / (2 * pi) * sqrt (k/m).

    since d = v*T, we can say v = d/t = d * f

    the final equation, after combining everything, is as follows:

    v = d / (2 * pi) * sqrt (k/m)

    by plugging everything in

    v =.75 / (2 * pi) * sqrt ((1 * 10^5) / (30))

    We find our velocity to be:

    v = 6.89 m/s
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