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8 September, 17:10

A car is moving with a velocity (3.0 m/s) € x ˆ + (1.0 m/s) € y ˆ and 3.0 seconds later its velocity is (6.0 m/s) € x ˆ - (3.0 m/s) € y ˆ. What is the direction of the average acceleration of the car?

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  1. 8 September, 17:18
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    -53.13°

    Explanation:

    Initial velocity, u = 3x + 1y

    Final velocity, v = 6x - 3y

    Time = 3s

    To find acceleration, a:

    a = (v - u) / t

    a = [6x - 3y - (3x + y) ] / 3

    a = (6x - 3y - 3x - y) / 3

    a = (3x - 4y) / 3

    a = x - 4/3y

    To fine the direction, we use:

    tanθ = y/x

    tanθ = (-4/3 / 3) = (-4/3)

    θ = - 51.13°
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