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4 April, 18:39

A 2500-kg vehicle traveling at 25 m/s can be stopped by gently applying the breaks for 20 seconds. What is the average force supplied by the breaks to stop the vehicle?

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  1. 4 April, 19:02
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    Momentum = (mass) x (speed)

    Change in momentum = (force) x (time)

    The initial momentum is (mass) x (speed) = 2500x 25 = 62,500 kg-m/s.

    Since you want to stop the vehicle, that number is also the required change

    in momentum ... you want the vehicle to wind up with zero momentum.

    62,500 = (force) x (time) = 20 x force

    Divide each side by 20:

    force = 62,500 / 20 = 3,125 newtons
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