Ask Question
5 February, 12:22

A compound is 24.7% calcium, 1.2% hydrogen, 14.8% carbon, and 59.3% oxygen. write the empirical formula and name the compound.

+2
Answers (1)
  1. 5 February, 12:39
    0
    For simplicity, assume that the total mass of the compound is 100 g.

    Therefore, by mass

    Ca = 24.7 g, H = 1.2 g, C = 14.8 g, and O = 59.3 g

    Converting these to moles

    Mol = mass*1/atomic mass

    Ca = 24.7*1/40.078 = 0.6163 mol Ca

    H = 1.2*1/1.01 = 1.1881 mol H

    C = 14.8*1/12.01 = 1.2323 mol C

    O = 59.3/16 = 3.7062 mol O

    Next, divide all the mols by the smallest value obtained.

    Ca: 0.6163/0.6163 = 1 mol Ca

    H: 1.1881/0.6163 = 2 mol H

    C: 1.2323/0.6163 = 2mol C

    O: 3.7062/0.6163 = 6 mol O

    Therefore, empirical formula of the compound is

    CaH2C2O6

    This compound is referred to as Calcium Bicarbonate
Know the Answer?