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28 January, 07:42

A 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7N. What is the acceleration of the box?

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  1. 28 January, 07:46
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    1.76 m/s^2

    Explanation:

    mass of box, m = 5.5kg

    net force, F = 9.7N

    acceleration = ?

    F = m x a

    a = F/m = 9.7/5.5

    a = 1.76 m/s^2
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