A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. the base plate rests on a concrete slab. determine the stress that the base plate exerts on the concrete slab. express your answer in units of (a) lb/in. 2 and (b) lb/ft2. (precision of 1 for (a) and of 1000 for (b))

Question

Aldo Moody

Physics

13 January, 12:56

A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. the base plate rests on a concrete slab. determine the stress that the base plate exerts on the concrete slab. express your answer in units of (a) lb/in. 2 and (b) lb/ft2. (precision of 1 for (a) and of 1000 for (b))

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Answers (1)

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Jett Friedman · Answer 1

We want to find the area of the plate in square inches and square feet.

1) Here we need inches. The area is 9in * 24in = 216 in.^2., since 1ft = 12in. 18,000lb / 216 in.^2 = 83lb/in.^2

2) Here we need feet. With 12 in = 1 ft, 9in =.75ft. The area is. 75ft * 2ft = 1.5 ft.^2

18,000lb / 1.5 ft.^2 = 12,000lb/ft.^2