According to Archimedes' principle, the mass of a floating object equals themass of the fluid displaced by the object. A swimmer is floating ina nearby pool; 95% of her body's volume is in the water while 5% of herbody's volume is above water. Determine the density of the swimmer's body. The density of water is Does your answer make sense? Whyor why not?

Question

Sarah Ayers

Physics

29 March, 04:14

According to Archimedes' principle, the mass of a floating object equals themass of the fluid displaced by the object. A swimmer is floating ina nearby pool; 95% of her body's volume is in the water while 5% of herbody's volume is above water. Determine the density of the swimmer's body. The density of water is Does your answer make sense? Whyor why not?

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Answers (1)

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Cora Camacho · Answer 1

Answer: 950 Kg/m^3

Explanation: We can deduce from the Archimedes principle that there is a relation between the density and the volumes displaced, as follows:

Density*Volume = Mass

So for equilibrium Density of body = Density of water * Vw/Vb

Being Vw/Vb the relation between the displaced water and the body volume, and given the water density as 1000 Kg/m^3 we got:

Density (B) = 0.95 * 1000 Kg/m^3.