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3 May, 08:31

A 28 g ball of clay traveling east at 3.5 m/s collides with a 35 g ball of clay traveling north at 2.8 m/s.

What is the movement direction of the resulting 63 g blob of clay?

What is the speed of the resulting 63 g blob of clay?

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  1. 3 May, 08:52
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    45 deg north of east

    2.3 m/s

    Explanation:

    Assuming east as directed along positive x-axis and north as directed along positive y-axis

    m₁ = mass of clay ball traveling east = 28 g

    v₁ = velocity of ball traveling east = 3.5 i m/s

    m₂ = mass of clay ball traveling north = 35 g

    v₂ = velocity of ball traveling north = 2.8 j m/s

    m = mass of the combination of two balls after collision = 63 g

    v = velocity of the combination after collision

    Using conservation of momentum

    m₁ v₁ + m₂ v₂ = m v

    (28) (3.5 i) + (35) (2.8 j) = 63 v

    98 i + 98 j = 63 v

    1.6 i + 1.6 j = v

    Direction:

    θ = tan⁻¹ (1.6/1.6)

    θ = 45 deg north of east

    Speed is given as

    |v| = sqrt ((1.6) ² + (1.6) ²)

    |v| = 2.3 m/s
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