A driver in a blue car traveling at 50 km h-1 sees a red car approaching in his rear view mirror. the red car is traveling at 60 km h - 1 and is 30 m behind the blue car when first spotted.

a. how many seconds from the time the driver of the blue car first noticed it until the red car passes the blue car?

b. how much farther down the road will the blue car travel in this time?

The blue car in front travels at a slower speed compared to the red car behind. Eventually, the red car would have to overtake the blue car because it is much faster. First, let's compute the time it takes before the red car catches up to the blue car. The solution is as follows:

30 m = (60 km/h - 50 km/h) * (1000 m/1 km) * (1 h/3,600 s) * (t)

t = 10.8 seconds

After 10.8 seconds, the red car catches up to the blue car. With this amount of time, the blue car would still cover additional distance. That would be equal to:

Distance = Speed*time

Distance = (50 km/h) * (1 h/3600 s) * (10.8 s)

Distance = 0.15 km