Unpolarized light of intensity i0 is incident on three polarizing filters. the axis of the first is vertical, that of the second is 43° from vertical, and that of the third is horizontal. what light intensity emerges from the third filter?

Question

Julianne West

Physics

14 May, 17:29

Unpolarized light of intensity i0 is incident on three polarizing filters. the axis of the first is vertical, that of the second is 43° from vertical, and that of the third is horizontal. what light intensity emerges from the third filter?

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Answers (1)

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Shaniya Rush · Answer 1

To determine the intensity, the key idea is to work through the system filter-by-filter and applying either the one-half rule for unpolarized light or the cosine-squared rule for an already polarized light.

When the light reach the first filter, it is unpolarized, so the intensity is:

I1 = 1/2 I0 (One-half rule)

Because the light reaching the second filter is polarized, given 43° angle difference, the intensity is:

I2 = I0 cos^2 (angle difference)

= I0 cos^2 43°

= 0.535 I0

Lastly, when the light reached the third filter, it is polarized and has angle diference equals to the angle between the second and last filter 47°. Using the same rule, we get:

I3 = I2 cos^2 47°

= (0.535 I0) cos^2 47°

= (0.535 I0) (0.465)

= 0.249 I0

So, the intensity which emerges is 0.249 I0.