Ask Question
17 February, 11:43

A uniform-density wheel of mass 9 kg and radius 0.40 m rotates on a low-friction axle. Starting from rest, a string wrapped around the edge exerts a constant force of 13 N for 0.72 s. (a) What is the final angular speed? Entry field with correct answer 5.2 radians/s (b) What was the average angular speed? Entry field with incorrect answer 1.872 radians/s (c) Through how big an angle did the wheel turn? Entry field with incorrect answer 1.3478 radians/s (d) How much string came off the wheel? Entry field with incorrect answer 0.8469 m

+2
Answers (1)
  1. 17 February, 11:53
    0
    Moment of inertia of wheel = 1/2 x mR², m is mass and R is radius of wheel

    =.5 x 9 x. 4²

    =.72 kg m²

    Torque created on wheel by string = T x r, T is tension and r is radius of wheel.

    13 x. 4 = 5.2 N m

    angular acceleration α = torque / moment of inertia

    = 5.2 /.72

    = 7.222 rad / s²

    a) final angular speed = α x t, α is angular acceleration, t is time.

    = 7.222 x. 72

    = 5.2 rad / s

    b)

    θ = 1/2 α t², θ is angle turned, t is time

    =.5 x 7.222 x. 72²

    = 1.872 rad

    average angular speed = θ / t

    = 1.872 /.72

    = 2.6 rad / s

    c)

    angle turned = 1.872 rad (discussed above)

    d)

    length of string coming off

    = angle rotated x radius of wheel

    = 1.872 x. 4

    =.7488 m.

    74.88 cm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A uniform-density wheel of mass 9 kg and radius 0.40 m rotates on a low-friction axle. Starting from rest, a string wrapped around the edge ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers