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26 October, 01:23

A student jumps straight up from a diving board that is 3.1 m above the water and hits the water 2.4 seconds later. With what velocity did the student Jump?

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  1. 26 October, 01:27
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    10. m/s

    Explanation:

    Given:

    y₀ = 3.1 m

    y = 0 m

    a = - 9.8 m/s²

    t = 2.4 s

    Find: v₀

    y = y₀ + v₀ t + ½ at²

    0 m = 3.1 m + v₀ (2.4 s) + ½ (-9.8 m/s²) (2.4 s) ²

    v₀ = 10.47 m/s

    Rounded to two significant figures, the student's initial velocity was 10. m/s.
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