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23 November, 16:53

A force of 60 pounds stretches a spring 1 inch from its natural position. Find the work (in in-lb) done in stretching the spring from its natural length of 10 inches to double that length.

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  1. 23 November, 17:11
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    50 lb

    Explanation:

    Force, F = 60 pounds

    extension in the spring, x = 10 inch = 10 / 12 foot

    Work, W = F x

    W = 60 x 10 / 12 = 50 lb
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