Ask Question
13 March, 04:39

A ball is kicked into the air at time t = 0. While the ball is in the air, its height above the ground after t seconds is - 16t^2 + 40t feet. How many seconds after the ball is kicked will it hit the ground?

+1
Answers (1)
  1. 13 March, 04:52
    0
    we are given the equation of the height of the ball through time which is - 16t^2 + 40t. The maximum height is obtained by differentiating the equation and equating to zero. That is 40 - 32t = 0. thus t is equal to 1.25 seconds. hence the answer is twice the time which is 2.50 seconds
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A ball is kicked into the air at time t = 0. While the ball is in the air, its height above the ground after t seconds is - 16t^2 + 40t ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers