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28 October, 20:15

How much heat is absorbed by a 71g iron skillet when its temperature rises from 11oC to 29oC?

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  1. 28 October, 20:45
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    The right formula to use for this calculation is the heat capacity formula,

    Heat absorbed, Q = MCT, Where

    M = Mass of the substance = 71

    C = Specific heat capacity for iron = 0.450 J/gc

    T = Change in temperature = 29 - 11 = 18

    Q = 71 * 0.450 * 18 = 575.10

    The amount of heat absorbed by the iron skillet is 575 J.
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